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An express train passes through a station. It enters with an initial velocity of 21.6 m/s and decelerates at a rate of O.158
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Guven data:- Vi= 21.6m/ a = – 0.158m/ x=217m. (6) W.KIT V = Vp + aan. → Vf = √ (21.62 - (2x 0.158x217) f = 19.95 m/s) (2) Now

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