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10. Elemental sulfur exists in two crystalline forms, rhombic and monoclinic. From the following data =...
Sulfur has two solid forms - a (or rhombic) and b (or monoclinic). The standard enthalpies of combustion, in which the product is s02. are -296.53 kJ/mol for S(s,a) and 296.86 kJ/mol for S(s,b) a 298 K. Find the standard reaction enthalpy for the process S(s,a) -> Sts,b) at 298 K.
What is the entropy of change when sulfur transition from rhombic to monoclinic forms?
From the following data, calculate the Enthalpy when Rhombic Sulphur is covered to monoclinic Sulphur S (rhombic) + O2 (gas) -----> SO2 (gas) delta H = -295.1 kJ/mol S (monoclinic) + O2 -------> SO2 (gas) delta H = -296.4 kJ/mol ___________________________________________________ S (rhombic) -------> S (monoclinic) delta H = [x] kJ/mon
Consider the phase transition between two phases of sulfur S(s, rhombic) S (s, monoclinic) IF AG for this transition is +0.10 kJ/mol and the densities of the rhombic and monoclinic phases are, respectively, 2.07 g/cm and 1.92 g/cm', at what pressure does the phase transformation from rhombic to monoclinic become spontaneous?
9.Enter your answer in the provided box. S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/mol S(monoclinic) + O2(g) → SO2(g) ΔHo rxn= −296.36 kJ/mol calculate the enthalpy change for the transformation S(rhombic) → S(monoclinic) (Monoclinic and rhombic are different allotropic forms of elemental sulfur.) _______kJ/mol 10. Enter your answer in the provided box Use the following data to calculate ΔHo/f for CS2(l): C(graphite) + O2(g) → CO2(g) ΔHo rxn= −393.5 kJ/mol S(rhombic) + O2(g) → SO2(g) ΔHo rxn=...
What is the standard Gibbs free energy for the transformation of diamond to graphite at 298 K? Cdiamond?Cgraphite Express your answer to three significant figures and include the appropriate units. Gibbs free energy is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, which is minimized at equilibrium. It is defined as G=H?TS Elemental carbon usually exists in one of two forms: graphite or diamond. It is generally believed that diamonds last...
The vaporization of compound A is described by the following chemical equation. A(1) A(8) A rap(72.39 °C) = 38.21 kJ/mol Calculate the entropy of vaporization, Aswap, for A(l) at 25.0 °C given that the boiling point of A is 72.39 °C, and the molar heat capacity of A(l) is 119.09 J/mol K). Assume that the molar heat capacity of A(R) is 56.5% of that of A(1). ASP J. mol-K Calculate the standard enthalpy of vaporization. A Hap, for A(1) at...
The molar enthalpy of fusion of solid bismuth is 11.0 kJ mol-1, and the molar entropy of fusion is 20.2 J K-1 mol-1. (a) Calculate the Gibbs free energy change for the melting of 1.00 mol of bismuth at 575 K. kJ (b) Calculate the Gibbs free energy change for the conversion of 5.12 mol of solid bismuth to liquid bismuth at 575 K. kJ (c) Will bismuth melt spontaneously at 575 K? (d) At what temperature are solid and...
Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the heats of formation of the substances involved in the reaction: ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants) Entropy change, ΔS∘, is a measure of the number of energetically equivalent microstates introduced into the system during the reaction. The degree of spontaneity of a reaction is represented by the Gibbs free...
The enthalpy of fusion of cadmium at its normal melting point of 321 °C is 6.11 kJ mol? What is the entropy of fusion of cadmium at this temperature? ASfus = J mol-K-1 The molar enthalpy of fusion of solid cadmium is 6.11 kJ mol-1, and the molar entropy of fusion is 10.3 JK+mol-1. (a) Calculate the Gibbs free energy change for the melting of 1.00 mol of cadmium at 622 K. (b) Calculate the Gibbs free energy change for...