From the following data, calculate the Enthalpy when Rhombic Sulphur is covered to monoclinic Sulphur S...

Question

Question

From the following data, calculate the Enthalpy when Rhombic Sulphur is covered to monoclinic Sulphur

S (rhombic) + O₂ (gas) -----> SO₂ (gas) delta H = -295.1 kJ/mol

S (monoclinic) + O₂ -------> SO2 (gas) delta H = -296.4 kJ/mol

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S (rhombic) -------> S (monoclinic) delta H = [x] kJ/mon

Answer 1

Answer #1

S (rhombic) + O2 (g) -----> SO2 (g) ,delta H = -295.1 kJ/mol -------------------------------equation 1

S (monoclinic) + O2 (g)-------> SO2 (g) ,delta H = -296.4 kJ/mol -------------------------------equation 2

subtract equation 2 from equation 1:

Write equation 1 in the top, followed by equation 2. [ as written above]
To subtract, give ( - ) sign to all components of equation 2 and now subtract similar components.
you can observe that O2 and SO2 get cancelled as they are in both equations.
We are now left with S (rhombic) - S (monoclinic) -----> 0 : which is S (rhombic) -------> S (monoclinic) --------------------equation 3
enthalpy for this equation 3 is obtained by subtracting enthalpy of equation 2 from 1
ANSWER = -295.1 kJ/mol - ( -296.4 kJ/mol ) = -295.1 kJ/mol + 296.4 kJ/mol = 1.3 kJ/mol

Answer 2

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