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mm Q2 (30 P) In the gear system the shaft rotates 1200 rev/min and transmits a power of 20 kW. Gears 2 and 3 have a normal mo

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Given na 1200 Rpm power = 20kw Torque Ta = Go, Goo X Power a Tin Go,000 820 QT X 1200 Ta = 159.15 Nom = 159,154 • qun-mm 2 egear foces b/w 4&5 Iz = Ty = (Pt), d3 = 613900. 200m 2. (Pt us 2x613900.26 - 2 T3 dy = 16,614.35N 73.9 (Pa) ur = (Pt. ) qs taConsidering cs in radice Plane T { foro RAGA RBr = 2068.94 N & MA=0 Ron 2668.94 (325) RB r = RAM 1034.470 Considering for inConsidering forces in tangential direction Eft=0 - Rett Ro = (PE) 23 +Ptyr = 21,537.36 EMA=0 Rot (135) = 4922-82 (102.5) + 16{ Mo =0=) Roa (135) = 9592.3 (70)- 2842.19 (1025) Roa = 3500.00 74AN Rca = 32 49.94N -). it PFt Pro PIO -PEL (Pt)us LED PEa (

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