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3500 3295 13 3148 77 3000 (Nonpolar) Cec sharp Medium 2501 1012 0=1 1709 SOCELL OOT 1506 457 43 1356 00 1148 29 1046 95 10055



This is a IR spectrum, I am trying to figure out if I am doing this right?Base on this graph I think I have alcohol for my unknown substance.

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Answer #1

Based on the given IR Spectrum, the unknown substance is:

amide (-CONH2).

3295-3198 cm-1 ---> two peaks, NH2 stretching,

2817 cm-1 ---> sp3 -C-H stretching,

1680 cm-1 ---> C=O (amide) stretching.

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