An object has a moment of inertia of 2.56 kg*m2 . What is the value of...
An object has a moment of inertia of 2.56 kg*m2
. What is the value of the torque needed to accelerate the
rotation of the object from rest to a rotation of 5 revolutions per second in 30 seconds?
answer is 2.68 N*m
What is the formula/ show work to solve
Thank you!!!
Homework Answers
T = I*alfa = I*(W2-W1)/t = (2.56*(5*2*3.14 - 0)/)30 2.68 Nm
W2 = 5rev/s = 5*2*pi rad/s
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