Question

5. Find the absolute maximum and absolute minimum values of the function f(x) = x.elfm) on the interval --2 < < 2. J 17 J 3.1.

Answer 1

sodbe #) = xem xefana] for contical points put f() = 0 >> xestelle - $ $x+1) = 0 e x 40 > 2x+1=0 [ x2]8,] Now Second derivative test "(x) = 3 2 x + 1) + 8 8 at x = - 3 f on = 0 +2 el yo I

=) flow is local Muruma at x==3 Now cheak on boundy points also X=-2. +(-2)=-2 e - - 3 = -0.527194 X=2 f (2) = 204/3 X=-3 = -00551819. Absolute maximum is at fx = 2, #2) = 24937 Absolute minimum is at x=- ++3)=-2012