Question

Consider the function f(0) = 2x3 + 6x² – 144x +1 with -6<< < 5 This function has an absolute minimum at the point and an absolute maximum at the point Note: both parts of this answer should be entered as an ordered pair, including the parentheses, such as (5, 11).

Answer 1

fix)= ax +62²1440+ riven function is solution - FIX) = 243 +682--14421+1 fill) = 622+122–144 and minimum value of food of 1 0 for maximum 672 +124-144 = 0 q2 + 2X – 24 = 0 2? +62-42-24=0 X(X +6)-418 +6)=0 (2-4) (X+6)=0 x=-614 if 2=-6 then 666) = 26-62466-6) 144 (+60+1 = 649 614) - 2.(4.2376(4)2-19414)+) =-35) thn if a = 4 f152 = 2150761533_144151+1= -463 minimum at the then absolute an if X= 5 has function The point &c x=5 an absolute maximum at the point azt and

fea)= a-alocal is Given function utions - f'(X)= + [a - a Ina] = 1-2 for maximum and minimum values of Fed) (a)=0 H-2 = 0 x=a if a = 1 / then f(!) = Į -2 10 ( ) = 478863 the if de q teen $12) = 2 – 2 In (2) = 0.6137 if a=5 then fl5 )=5-a ln (5)=1-78 The absolute masimum value is [1.8863 ] af and this occurs at The absolute minimum value is 10.61371 and this occurs ata=a/