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A student was able to separate the three components of a mixture via liquid chromatography. She obtained 1.33 g of component
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mA = 1-33gm mg=0.970 gm, me=0.350gm mTotal = mAtmB t mc = 2.65 gm. % mass of MA in 1033 xloo = 50.2 % A = - Total 10 do mass

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