Question

3. Use the circuit below to answer the following questions. The switch has been in the initial position shown for a long time. At t=0, the switch disconnects the 2 V source from the circuit with R2, L1, and Ci, and connects to Il and Ri. S1 t=0 R2 L1 1000 33mH 1A 31000 2v C1 +1 47uF Fill in the table below. Please remember to include units with your answers. Immediately before 1-0. Immediately after 1-0. Long after 1 = 0. t=0 1 = 0 100 IL = il= VL = Vc = 25 points

Answer 1

ay you al do D-1A Apple Under Stendly Steute Inductal cockt og Rhorst cincuit and capacitat acts as open cistit. 16+)-1; (0) = 0. y lot)= k 6) = 2V V2 6+)= V26-) = OV ho (64)= 116) = ov for to TODS 33 MH # pit suf Dola 100 Dela I (c) = 0, ve loc)0 : I (a)=0 @)=01*100 = 10V tyo 29) = Rull (R2+S4 + Śc,) - R. x (R2 + $4, + $i? Rt R2 + SLi + sci 26) ? (s²4e + Sera + 1) Ri 524,61 + Sci (R1+R2) + 1 28) - LG ( 3*+ sx R2 + tocil RI 니디 Si (s² + sxG (Ritre) & /al (82+s4R244) + 5c, dar, s²+ sx Ritke the

w tie, 331464 47* 10 6 = 644745-22 2&wn= Rita rw=802.96 100+100 = 6060.60 5 33x10 3 Ş = 6060.60 axwn GO 60.60 2x 202.96 { = 3.77 { > 1 & overdamped system. a mm 1001 334f 1002 - къце IA zov convert current source into Voltage source Apply eapeace TIF Conve memem laz 1007 LS - Vse Apply Kve in loop -1015 +100+100) $6) + ?($)LS + 16)x'/se + vclot) -0. 1Q)( 200+ ls + *sc} = 40 - vet) 161 ( boxca +] = 10 I@) ( 200 X5C + L + 10-2 $Ć 8XC IS) = (22(Lc] + sx 2000 + 1) L¢ ( 32+ 3x260 + Yes]

52 - 200 - 3376 + 6H4745:32. 242642 s2+ 60606606 S 644745.१ 2- - 24 2012 9.46)= (5+ 168-31) (e+sas2)

let R42042 s +108-31) (5+5952) To tl (sit 108-31) + S+5952 A(s+5952) + B (s+109631) = 242642 let SS-108231 = As 0-04848 Śs-5952 B9 -0.04148. OcOHI48 I (S) = E 0004148 ist 103-31) 3+5952 Apply Inverse laplace Ilf i) = 0.04148 € 108.214_ orohl48 €5952€ Ve(t)= ¿j istat K 14 = Hit KO04148 (e-f08-31€ 259524 Mees = 882-353038€ - 499521) 8-316 NE).= 882.553 e-5952E) 108-31 -5952 Nolits.