Question

9. Wire 1 and wire 2 are two parallel, horizontal wires. The current in wirel is SA moving to the left, and the current in wire 2 is 10 A, moving to the right. The wires are 15 cm apart, the point P is 5 cm from wire 1. point Q is 5 cm from wire 2, and point R is 5 cm from both point and wire 2. -P Scm SA wire 1 Sem 5cm -R 5cm 10A OE > wire 2 (a) What is the direction of the net magnetic field at P, Q and R? (b) is the magnitude of the net magnetic field greatest at point P, Q or R? (c) Find B,, the magnetic field at point S, due to wire 1. (d) What is the direction of B,? (e) Find By, the magnetic field at point T, due to wire 1. (h) What is the direction of the magnetic force on wire 2 due to wire 1? (g) What is the magnitude of the magnetic force exerted on a 2 m length of wire 2?

Answer 1

f F = I2XB) Fall I x B) F = L[ ZXB} After taking cross-product, Director of magnetic force cail be right side of wire 2, 192 E IL B sino, 9 - 10° Bien F = lox 2x066x10-5 If= 1:32X10-AN

B, due to wire Hot upwarda-ive kar, L Downward-tive Bhet 5 ho 2A L5x102 Jo 2oxl02 Bren -t 105T (Doconward

Bhet Il Iz of + 2 Ho YA ri 912 Bnet S 2-2x10-7 Lsxio-2 + lox102 Bher = -2x107 77 1 +1]xlə? Bher -4X10 Tesla

Direchon upward Chid To I I het QA '16 --2x10-7 [s 5 + Jo 58102 ·loxlo-2 ~2x10-51 1 2. て --2410-5 [ -5xlost Direction, upward