Question

If the first minimum (m = 0) in a Young’s double slit experiment is found at 10.2° when yellow (580 nm) light is used, at what angle will the second-order maximum (m = 2) for red (640 nm) light be found?

Answer 1

for young's double slit experiment condition for minima . dsno = (m + ₂) + for m=2 a 0 = 10.2 & a=58ohm d fin(10.2) = (2++) (soo xloom) - 0

1 for maxima dl Sim o= mi m=2 x=640nm d sno=(2) (640x58 m) dividing ® by o I sino (2)(640 xrons) dsm (10.2) : (2+1/2) (580x102) Sino 2 x640 Sin (10.2) 2.5×580 Sin o= 0.15632 0 = go