Question

PRINTER VERSION BACK NEXT Chapter 07, Problem 28 After skiding down a snow-covered hill on an inner tube, Ashley is coasting across a level snowfield at a constant velocity of +2.0 m/s. Miranda runs after her at a velocity of +5.1 m/s and hops on the inner tube. How fast do the two of them slide across the snow together on the inner tube? Ashley's mass is 58 kg, and Miranda's is 72 kg. Ignore the mass of the inner tube and any friction between the inner tube and the snow.

Answer 1

mass of Ashley, n. = 58 kg velocity of Ashley , .= 2 rufe mass of Miranda, m2 = 72 kg velocity of Miranda, 2 = 5.1 m/s Momentum will be conserved. .: mv + made = m. + m₂) v V = mus, & m₂ V₂ miem, 58 x 2 + 72x 5.1 58 +72 30 an when mi= 2.6 kg. m₂ = V, 9 kg 22 m/s , miv, + m₂ V2 of 9x22 2.6 +9 miem, - 17.07 m/s (6) when w = 22 es va = 0 then y = 2.6x22 to - 2.6+ 9 4.93 m/s

mass of batman, M = 96.5kg initial relocity of Batman, u = 0 mass of boat, M₂ = 695 kg initial velocity of boat , 2 = 10.6 m/s i Final relocity = m. Vit MzY2 mm I = 0 + 695x10.6 96.5+ 695 - 9.3 eh A, VOA = 5, 7 m/s and that of B. Initial relocity of Calong x axis) Vo = 0 Momentan will be conserved in both x and Along x - axis, MAVOA & MoVoox = MAVAX + Moysex + 0.039 x 5.7 + 0 = 0.039 fa coses" 0.07 8 Vse cos 370 7 0.01648 V + 0.0623 y = 0.2223 Along y-axis, MAVony + me loby = MAY SANG + Mavi By > 0+0 = 0.039/A Sin 650 - 0.0 78 sin 37°

0.078 Sin 370 VIB 0.0 39 sin65° ② » TA = 1.328 Vte - Substitute ② in 0 : 0.01648 1.328 & 0.062 3 Vee = 0.22 23 ufo = 8.64 mis and use = 1.328 x 2.64 = 3.506 m/s (an 3.506 ross 67 2.64 m/s