Question

Three students named Abe, Bob, and Carl make measurements of the length of a table using a meter stick. Each student's measurements are tabulated in the following table. Modern laser technique made a value of 3. 475 m in this measurement 3. Student L L2 Abe 3.471 3.475 3.473 3.478 Bob 3.484 3.481 3.479 3.482 Carl 3.466 3.477 3.464 3.474 L3 On-1 lun 1) Find the percent error of Bob 2) Find the percent difference between and Abe and Bob 3) Find the uncertainty of measurement of Carl 4) Find the measurement of Bob. 5) Make a graph of Length vs Trials for three students (Spread Sheet like MS Excel).

Answer 1

laser technique mode a value -3.475 i)Find the percent error of bob: - % Error bob: delta L_1 = 0.004 delta L_2 = 0.006 delta L_3 = 0.004 delta L_4 = 0.007 delta L bar = delta L_1 + delta L_2 + delta L_3 + delta L_4/4 delta L bar = 0.004 + 0.0006 + 0.004 + 0.007/4 delta L bar = 0.00525 therefore % Error = 0.00525/3.475 times 100 % Error = 0.1510% 2) % difference b/w and A be & bob: - Consider a A be & bob: \r\n we know that, delta L_1 = 0.004, delta L_2 = 0.006 delta L_3 = 0.002, delta L_4 = 0.007 delta L bar = 0.004 + 0.000 + 0.002 + 0.007/4 delta L bar = 0.013/4 = 0.00325 delta L bar/L = 0.00325/3.475 times 100 = 0.0935 % difference = 0.144 - 0.0935 % difference = 0.0505 Find the uncertainity of measurement of carl: - carl = 0.009 + 0.002 + 0.011 + 0.001/4