Question

3. Three students named Abe, Bob, and Carl make measurements of the length of a table using a meter stick. Each student's measurements are tabulated in the following table. Modern laser technique made a value of 475 m in this measurement. 5.415 Student L し2 L3 L4 Abe 5.471 5.475 5.473 5.478 Bob 5.484 5.481 5.479 5.482 Carl 5.466 5.477 5.464 5.47 On-1 1) Find the percent error of Bob 2) Find the percent difference between and Abe and Bob 3) Find the uncertainty of measurement of Carl 4) Find the measurement of Bob. 5) Make a graph of Length vs Trials for three students (Spread Sheet like MS Excel).

Answer 1

"For Bod: L_1 = 5.484, L_2 = 5.481 L_3 = 5.479, L_4 = 5.482. so because actual length of table is calculate, so by modern laser technique, that is 5.475m. so now L = 5.475m (actual length) delatL_1 = L_1 - L = 5.484 - 5.475 = 0.009 delatL_2 = L_2 - L = 5.481 - 5.475 = 0.006 delatL_3 = L_3 - L = 5.479 - 5.475 = 0.004 delatL_4 = L_4 - L = 5.482 - 5.475 = 0.007