ANSWER :
f(x) = 1/x - sqrt(x + 3) / (x - 2)
At x = 0 and at x = 2, f(x) becomes infinite. Hence, these are not in the domain.
As per square root rule, we can not get real values for square root of a negative value.
Hence, x + 3 ≥ 0
=> x ≥ - 3
Therefore, x can be any value greater than or equal to - 3 except 0 and 2.
Hence, domain in interval notation is as under :
Domain : [ - 3, 0) U (0, 2) U (2, ∞). (ANSWER)
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