Balance the following equation in acid.
Br2(aq) Br-(aq) + BrO-(aq)
Can you explain how to get the answer?
Br2(aq) Br-(aq) + BrO-(aq)
0 -1 +1 -2
Step 1- Balance the atom being reduced/oxidized.
Step 2- Balance the oxygens- by adding H2O
Step 3 - Balance the hydrogens- by adding H+
Step 4- Balance the total charge - by adding e-
1-Oxidation 1/2 Reaction ------->Br2 ---->2 BrO-
reduction 1/2 reaction ------> Br2 --->2 Br-
2 - Br2+2H2O---->2BrO- (oxidation)
Br2---->2Br-(red.)
3- Br2+2H2O---->2BrO- +4H+ (oxd)
Br2---->2Br-(red.)
4- Br2+2H2O---->2BrO- +4H+ +2e- (oxd)
Br2 + 2e- ---->2Br-(red)
2Br2 +2H2O -----> 2Br- + 2BrO- +4H+
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