Ans. We calculate all probabilities using R:-
1. P(z>0.23 or z<-0.23) =P(z>0.23 ) + P( z<-0.23)
> pnorm(.23,0,1,lower.tail=F)+pnorm(-0.23,0,1)
[1] 0.8180918
P(z>0.23 or z<-0.23) = 0.8181
2. P(-3<z<0) = P(z<0) - P(z<-3)
> pnorm(0,0,1)-pnorm(-3,0,1)
[1] 0.4986501
P(-3<z<0) = 0.4987
3. P(-0.23<z<2.35) = P(z<2.35) - P(z<-0.23)
> pnorm(2.35,0,1)-pnorm(-0.23,0,1)
[1] 0.5815674
P(-0.23<z<2.35) = 0.5816
4. P(z>1.47 or z<-1.47) =P(z>1.47 ) + P( z<-1.47)
> pnorm(1.47,0,1,lower.tail=F)+pnorm(-1.47,0,1)
[1] 0.1415618
P(z>1.47 or z<-1.47) = 0.1416
5. P(z<-2 or z>-1) = P(z<-2) + P(z>-1)
> pnorm(-2,0,1)+pnorm(-1,0,1,lower.tail=F)
[1] 0.8640949
P(z<-2 or z>-1) = 0.8641
6. P(-3<z<3) = P(z<3) - P(z<-3)
> pnorm(3,0,1)-pnorm(-3,0,1)
[1] 0.9973002
P(-3<z<3) = 0.9973
P(z>0.23 or z<-0.23) = P(-3<z<O) = P(-0.23<z<2.35) = P(z>1.47 or z<-1.47) = P(z<-2 or z>-1) =...
Question 3 2 pts Find P(z>2.35) = Round to 4 decimal places.
Question 2 2 pt Find P(z<2.35)= Round to 4 decimal places.
Question 4 2 pts Find P(-1.47< z< 1.79) = places. Round to 4 decimal
Question 1 1 pts To find P(z<2.35), where do you shade? left Oright between
Let the random variable Z follow a standard normal distribution. Find P(-2.35 < Z< -0.65). Your Answer:
Question 35 Using the Standard Normal (Z) Distribution Table, find P (Z> 0.52) O .3015 O .3446 .6554 O .6985
Solve: Laurent series h(z) - Z O CIZ + 11 <3 (2+1)(2-2)
b. P(-1.69 SZ SZ) = 0.9545 C. P(Z > 20) = 0.0048 d. P(Z, SZS 2.00) = 0.1359 e. P(Z > Z) = 0.9713 f. PC-Z, SZSZ) = 0.2358
Question 2 (1 point) Let z is standard normal variable. Find P(z> - 2.67) O 0.9962 0 0.0937 0.937 0.0038 0.063 Previous Page Next Page
5. Find the Fourier Transform of g(t) = {o. (1-x?, x<1, 1</z/.