What is the final temperature when 100 g of iron at 90 degrees Celsius is placed in 400 g of water at 25 degrees Celsius? The specific heat capacity of iron 0.45 J/g*K and the specific heat capacity of water is 4.184 J/g*K
let the final temperature be 'T' K
now, heat lost by iron = mass of iron * specific heat capacity of iron*change in temperature
or, heat lost by iron = 100*0.45*(363-T) {temperature of iron initially =273+90=363 K)
or, heat lost by iron = 45*(363-T)......................(1)
now, heat gained by water = mass of water * specific heat capacity of water*change in temperature
or, heat lost by iron = 400*4.184*(T-298) {temperature of water initially =273+25=298 K)
or, heat lost by iron = 1673.6*(T-298)......................(2)
since(1) =(2)
therefore, 45*(363-T) = 1673.6*(T-298)
or, T= 299.7K
What is the final temperature when 100 g of iron at 90 degrees Celsius is placed...
What is the final temperature when 100 g of iron at 90 degrees Celsius is placed in 400 g of water at 25 degrees Celsius? The specific heat capacity of iron 0.45 J/g*K and the specific heat capacity of water is 4.184 J/g*K.
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