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Part I) A 15.6 cm -diameter circular loop of wire is placed with the plane of...

Part I) A 15.6 cm -diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the pole pieces of a large magnet. When 4.35 A flows in the coil, the torque on it is 0.125 m⋅N . What is the magnetic field strength? Part II) Suppose the rod in the figure has mass m = 0.38 kg and length 28 cm and the current through it is I = 29 A . a) If the coefficient of static friction is μs = 0.53, determine the minimum magnetic field B⃗ (not necessarily vertical) that will just cause the rod to slide. Give the magnitude of B⃗ . b)Give the direction of B⃗ relative to the vertical (outwards towards us).
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