A circular coil consisting of a single loop of wire has a radius of 8.28 cm and carries a current of 9.16 A. It is placed in a uniform external magnetic field, so that the normal to the loop makes an angle of θ = 80.4° with the direction of the field.
If the coil feels a torque of 1.39×10−2 Nm, what is the magnitude of the magnetic field?
Torque = N i A B sin(theta)
1.39x10-2 = 1 x 9.16 x pi x 0.08282 x B x sin(80.4)
B=0.071455 Tesla
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