Question

c++ questions

Write a function that returns a pointer to the maximum value of an array of ints: int* ptrToMaximum(int* array, int* end); You don’t have to worry about what happens if end points beyond end(array). Maybe it is nice to allow end to point to before end(array). In the case that (array == end), you should return nullptr. Running the following main function should result in 8 7 being printed to the console. int main() { int a[] = {1,2,3,4,5,6,7,8,7,6,5,4,5,6,5,4,3,4,5,4,3,2,1}; int* maximum = ptrToMaximum(a,end(a)); cout << *maximum << " " << *(maximum+1) << endl; return 0; }

Answer 1

#include <iostream>

using namespace std;

int *ptrToMaximum(int *array, int *end) {
    if (array == end)
        return nullptr;
    int *max = array;
    while (array < end) {
        if (*array > *max)
            max = array;
        array++;
    }
    return max;
}

int main() {
    int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 7, 6, 5, 4, 5, 6, 5, 4, 3, 4, 5, 4, 3, 2, 1};
    int *maximum = ptrToMaximum(a, end(a));
    cout << *maximum << " " << *(maximum + 1) << endl;
    return 0;
}

Answer 2

#include <iostream>

using namespace std;

int *ptrToMaximum(int *array, int *end) {
    if (array == end)
        return nullptr;
    int *max = array;
    while (array < end) {
        if (*array > *max)
            max = array;
        array++;
    }
    return max;
}

int main() {
    int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 7, 6, 5, 4, 5, 6, 5, 4, 3, 4, 5, 4, 3, 2, 1};
    int *maximum = ptrToMaximum(a, end(a));
    cout << *maximum << " " << *(maximum + 1) << endl;
    return 0;
}