TRADITIONAL METHOD
given that,
standard deviation, σ =2
sample mean, x =9
population size (n)=10
I.
standard error = sd/ sqrt(n)
where,
sd = population standard deviation
n = population size
standard error = ( 2/ sqrt ( 10) )
= 0.632
II.
margin of error = Z a/2 * (standard error)
where,
Za/2 = Z-table value
level of significance, α = 0.1
from standard normal table, two tailed z α/2 =1.645
since our test is two-tailed
value of z table is 1.645
margin of error = 1.645 * 0.632
= 1.04
III.
CI = x ± margin of error
confidence interval = [ 9 ± 1.04 ]
= [ 7.96,10.04 ]
-----------------------------------------------------------------------------------------------
DIRECT METHOD
given that,
standard deviation, σ =2
sample mean, x =9
population size (n)=10
level of significance, α = 0.1
from standard normal table, two tailed z α/2 =1.645
since our test is two-tailed
value of z table is 1.645
we use CI = x ± Z a/2 * (sd/ Sqrt(n))
where,
x = mean
sd = standard deviation
a = 1 - (confidence level/100)
Za/2 = Z-table value
CI = confidence interval
confidence interval = [ 9 ± Z a/2 ( 2/ Sqrt ( 10) ) ]
= [ 9 - 1.645 * (0.632) , 9 + 1.645 * (0.632) ]
= [ 7.96,10.04 ]
-----------------------------------------------------------------------------------------------
interpretations:
1. we are 90% sure that the interval [7.96 , 10.04 ] contains the
true population mean
2. if a large number of samples are collected, and a confidence
interval is created
for each sample, 90% of these intervals will contains the true
population mean
Answer:
Upper confidence interval for the mean value of DC voltage values
is 10.04
In a Laboratory work, values of DC voltage circuit load were recorded drop as on 9.0....
A common-emitter BJT amplificr is shown in Fig.8.1. Note the DC biasing values and the BJTsmall-signalmodel parameters from the class-signment #9 on DC Bia ing. Neglect the value of Rs in your calculations, k1 Rs-a k2: 1· Cal ulatethesmall-agalpannetas ofthe amplifi randcompletethecalculated valuesinTable8-1 Smalls-signal voltage gai, AVk Small-signal input resistance,k, Small-signaloutput resistance, Ro VW RC 2k C2 RB 570k Rs C1 1 10uP 0.1m 1 Vs CE RE 2k SINE(0 1mV 1kHz 0 0 00) tran 0 2ms 0 1us...
Laboratory 2: Transistor circuit characteristics A. Objectives: 1. To study the basic characteristics of a transistor circuit. 2. To study the bias circuit of a transistor circuit. B. Apparatus: 1. DC Power supply 2. Experimental boards and corresponding components 3. Electronic calculator (prepared by students) 4. Digital camera (prepared by students for photo taking of the experimental results) 5. Laptop computer with the software PicoScope 6 and Microsoft Word installed. 6. PicoScope PC Oscilloscope and its accessories. 7. Digital multi-meter....
summatize the following info and break them into differeng key points. write them in yojr own words apartus 6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...