Homework Answers
initial concentration of KIO3 = 0.00364 M
Explanation
Total volume = 20.0 mL + 10.0 mL + 80.0 mL = 110.0 ml
According to dilution law, C1 * V1 = C2 * V2
C1 = concentration before mixing = 0.0200 M
V1 = volume before mixing = 20.0 mL
C2 = concentration after mixing
V2 = volume after mixing = 110.0 mL
C2 = C1 * (V1 / V2)
C2 = 0.0200 M * (20.0 mL / 110.0 mL)
C2 = 0.0200 M * (0.182)
C2 = 0.00364 M
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