a rate is equal to 0.0200 M/s. if [A] = 0.100M and rate =K[A]^0[B]^2, what is...
what could it be??? i was wrong A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = k[A]º, what is the new rate if the concentration of [A] is increased to 0.200 M? 0.0400 M/s 0.0600 M/s 0.0200 M/S 0.0800 M/S Incorrect Question 7 Arate is equal to 0.0200 M/s. If[A] = 0.100 M and rate = k[A]º to 0.200 M? 0.0200 M/S 0.0600 M/S 0.0400 M/s 0.0800 M/S
Chemical Kinetics 22. Given the following balanced equation, determ ng balanced equation, determine the rate of reaction with respect to (SO2). 2 502(g) + O2(8) - 2 SO3(g) A) Rate = 1152 B) Rate = 415021 C) Rate = + A[S021 D) Rate = . 3 A[SO21 E) It is not possible to determine without more information. [All, what is the new rate if the 25. A rate is equal to 0.0200 M/s. IFTA] = 0.100 M and rate concentration...
A reaction has the following experimentally determined rate law: rate = k[A]”[B] If the rate is 0.0100 M/s when [A] = 0.100 M, [B] = 0.100 M, what would be the rate if the concentration of A was increased to 0.300 M while the concentration of B was not changed? 0.0200 M/s 0.0600 M/s 0.1800 M/s 0 0.0900 M/s 0.0300 M/s
A reaction has the following experimentally determined rate law: rate = k[A]?[B] If the rate is 0.0100 M/s when [A] = 0.100 M, [B] = 0.100 M, what would be the rate if the concentration of A was increased to 0.300 M while the concentration of B was not changed? 0.0600 M/s 0.0200 M/s 0.0300 M/s 0.1800 M/s 0.0900 M/s
Question 13 (5 points) A reaction has the following experimentally determined rate law: rate = k[A]”[/B] If the rate is 0.0100 M/s when [A] = 0.100 M, [B] = 0.100 M, what would be the rate if the concentration of A was increased to 0.300 M while the concentration of B was not changed? 0.1800 M/s 0.0200 M/S 0.0600 M/S 0.0300 M/s 0.0900 M/s
b. Initial rate data for the reaction are tabulated below: Exp# [H2SO3];, M (Br), M (H), M Initial rate, M/s 0.0200 0.0400 0.0300 1.66 x 10-5 2 0.0400 0.0400 0.0300 3.32 x 10-5 3 0.0200 0.0800 0.0300 13.28 x 10-5 4 0.0200 0.0400 0.0600 6.64 x 10-5 5 0.0300 0.0200 0.0500 ? Write the rate law for the reaction. Show work. c. What is the order of the reaction in bromide ion? d. Calculate the numerical value of the rate...
The reaction A→BA→B has been experimentally determined to be second order. The initial rate is 0.0100 M/sM/s at an initial concentration of AA of 0.100 MM. Part A What is the initial rate at [A]=0.400M[A]=0.400M? What is the initial rate at ? 0.00250 M/sM/s 0.160 M/sM/s 0.0100 M/sM/s 0.0400 M/s
[A] (2) Consider this reaction: 2A + 2B → 2C+D (2.5 pts) [B] Initial Rate(M/s) (a) Write the rate law for this reaction 0.400 0.0100 5.90 x 10-6 (6) Calculate the rate constant. Include Units. 0.400 0.0400 9.44 x 105 (c) Is the reaction in an elementary reaction? Explain 0.400 0.0800 3.78 x 10-4 your answer in a sentence. 0.800 0.0600 2.12 x 10-4 (3) Here is a reaction: A products (1.5 pt) 0.800 0.0400 9.44 x 10-5 (3a) How...
The reaction B ➔ products follows the rate law Rate = k [B]2. If the initial concentration of B is 0.400 M, it requires 100 seconds for [B] to fall to 0.200 M. The additional reaction time (in seconds) that is required for [B] to reach 0.100 M is A. 125 B. 175 C. 100 D. 150 E. 200
Write a rate law for the reaction. Write a rate law for the reaction. Rate=k Rate=k[A] Rate=k[A]2 Rate=k[A]3 Exercise 14.40 - Enhanced - with Feedback 10 of 32 > A Review | Constants Periodic Table The following reaction is first order in N, 0, N20(g) NO: (C) + NO2(g) The rate constant for the reaction at a certain temperature is 0.053/s. What would the rate of the reaction be at the same concentration as in Part A if the reaction...