Problem 2. (15 Pts) Julian Stewart invested $280,000 in a limited partnership to drill for natural gas. The investment yielded annual returns of $45,000 the 1st yr, followed by $10,000 increases until the 6th yr, at which time an additional $180,000 had to be invested for deeper drilling. Following the 2nd drilling, the annual returns decreased by $10,000 per year, from $85,000 to $5,000. Using Excel, the IRR = 15.28%. a)Plot future worth as a function of MARR and. b)Plot future worth as a function of MARR • (MARR ranges from -50% to +50% increment by 5%) c)Determine the MARR that maximizes FW
Julian stewart invested $280000 in a limited partnership to drill for natural gas. The investment yielded annual returns of $45000 the Ist yr, followed by $10,000 increases until the 6th yr, at which time an additional $ 180,000 had to be invested for deeper drilling. Following the 2nd drilling, the annual returns decreased by $ 10000 per year, From $85000 to $ 5000. Using Excel IRR = 15.28%. Plot future worth as a function of MARR..
Internal Rate of Return (IRR) is a metric used in capital budgeting to estimate the profitability investments. Internal rate of return is a discount rate that makes the net present value (NPV) of all cash flows . IRR calculations rely on the same formula as NPV does.
IRR = Internal rate of return = i*
The following is the formula for calculating NPV:
Ct = net cash inflow during the period t
Co= total initial investment costs
r = discount rate, and
t = number of time periods
MARR = Minimum attractive rate of return
IRR>MARR for a profitable venture.
Use i = MARR for
CBj>0 (Positivecash
balance)
Use i = IRR (estimate) for
CBj<0 (Negative cash
balance)
Use Trial and error with IRR guesses to get CBN=0.
Since at N with i* CBN=0.
MARR is applied to (+) cash balances as if they were being invested
at MARR for that year
Problem 2. (15 Pts) Julian Stewart invested $280,000 in a limited partnership to drill for natural...