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0.044 Question 5 (1 point) Provide an appropriate response. In one city, 24% ofadults smoke. In groups of size 130 of adults,
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Answer #1

5) Binomial distribution

n = 130

P(an adult smokes), p = 0.24

q = 1 - p = 0.76

Variance = npq

= 130 x 0.24 x 0.76

= 23.71

6) Binomial distribution: P(X) = nCx px qn-x

P(a household has vcrs), p = 0.70

q = 1 - p = 0.3

Number of households, n = 15

P(number of households with vcrs is between 10 and 12, inclusive) = P(10)+ P(11) + P(12)

= 15C10x0.710x0.35 + 15C11x0.711x0.34 + 15C12x0.712x0.33

= 0.2061 + 0.2186 + 0.1700

= 0.5947

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