The voltage across the two resistors are the same
since P = V I
Where V is the voltage and I is the current through the bulbs
So the current and the power are proportional quantities.
P = I2 R
Since the power and the current are proportional quantities, For
the bulbs with greater power, the current through them will be
higher, so the resistance is smaller
For the 100 W bulb , the resistance is greater compared to the bulb
with 60 W power
The voltage across the two resistors are the same
since P = V I
Where V is the voltage and I is the current through the bulbs
So the current and the power are proportional quantities.
Also P = I2 R
Since the power and the current are proportional quantities, For
the bulbs with greater power, the current through them will be
higher, so the resistance is smaller
For the 100 W bulb , the resistance is greater compared to the bulb
with 60 W power
Two light bulbs of 60 watts and 100 watts are wired in parallel. What light bulb...
A 12-volt battery is connected to two light bulbs, as drawn in Figure 1. Light bulb 1 has resistance 3 ohms, while light bulb 2 has resistance 6 ohms. The battery has essentially no internal resistance, and all the wires are essentially resistanceless, too. When a light bulb is unscrewed, no current flows through that branch of the circuit. For instance, if light bulb 2 is unscrewed, current flows only around the lower loop of the circuit, which consists of...
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Two light bulbs are connected in parallel, and then connected to a battery, as shown in Fig. 4.51(a). You observe that bulb 1 is twice as bright as bulb 2. Assuming that the brightness of a bulb is proportional to the power dissipated in the bulb’s resistor, which bulb’s resistor is larger, and by what factor? The bulbs are now connected in series ,as shown in Fig.4.51(b). Which bulb is brighter, and by what factor? How bright is each bulb...