D Question 24 7 pts Suppose that replacement times for timing belts in cars are normally...
Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 years and a standard deviation of 1.1 years. Find the replacement time that separates the top 3% from the bottom 97% . Round your answer to 3 decimal places.
Suppose that replacement times for washing machines are normally distributed with a mean of 11 years and a standard deviation of 19 years Find the replacement time that separates the top 18 from the botom 82% Round to the neareste Click to view.nage the love of the O A 12 years OB 127 years O C. 113 years OD 9 years
15) Assume that z scores are normally distributed with a mean of 0 and a standard deviation 15) of 1. If P(z> c) 0.109, find c. olve the problem. 16) 16) Scores on an English test are normally distributed with a mean of 37.4 and a standard deviation of 7.9. Find the score that separates the top 59% from the bottom 41% 17) Suppose that replacement times for washing machines are normally distributed with a 17) mean of 10.9 years...
Solve the problem. Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 years and a standard deviation of 1.1 years. Find the probability that 70 randomly selected washing machines will have a mean replacement time less than 9.1 years. Write your answer as a decimal rounded to 4 places.
Question 9 (1 point) Suppose that replacement times for washing machine parts are normally distributed with a mean of 12.3 years and a standard deviation of 2.1 years. Find the oth percentile. Round to 1 decimal place. 9.4 years 14.1 years 12.7 years 15.2 years
Scores on a test are normally distributed with a mean of 63.2 and a standard deviation of 11 7 Find P81 , which separates the bottom 81% from the top 19%, Round to two decimal places. O A. 66.60 O B. 0.29 ОС. 088 O D. 73.47 Scores on a test are normally distributed with a mean of 63.2 and a standard deviation of 11 7 Find P81 , which separates the bottom 81% from the top 19%, Round to...
Replacement times for televisions are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years. Find the probability that a randomly selected television will need a replacement time less than 6 years.
Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 6.7 years and a standard deviation of 1.6 years. Find the probability that a randomly selected DVD player will have a replacement time less than 2.2 years? P(X < 2.2 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. If the company wants to provide a...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 3.8% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 1.3% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...