Question

The chief of security for Mall of the Dakotas was directed to study the problem of missing goods. He selected a sample of 200

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Answer #1

SOLUTION:

From given data,

We test this with chi-square goodness of fit test.

Null hypothesis : : True proportions in all 3 categories is equal to their claimed value. that is = 0.5 , = 0.25 , = 0.25

Alternative hypothesis : : Alternative one proportions is different from its claimed value.

Atleast one do not matched the claimed value.

Expected fraction(p) Observed (O) Expected (E = n*p) (O-E)^2 /E
0.5 110 100 1
0.25 50 50 0
0.25 40 50 2
O = n = 200 = (O-E)^2 /E = 3

Value of chi-square:

= ​​​​​​​ (O-E)^2 /E

= 1+0+2

= 3

Decision Rule :

Significance level = 0.1

Degree of freedom = df = k-1 = 3-1 = 2

Critical value = = 4.605

Decision Rule : Reject if > 4.605

Decision Regarding ?

Test statistic is not greater than critical value ,We fail to reject null hypothesis .At 10% level,there is NOT significance evidence that atleast one of the proportions differs from its claimed value.

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