Question

in C++, please show the work step by step. thanks

1.Write pseuodocode for a function that finds the minimum element in an array.

2. Translate your pseudocode from 1 into C++ code. Add a main function that calls the function appropriately.

3.First, wrap your head around what this function does:

bool isfact(int n){

bool is=false;

int fact=1;

for(int i=1; i<n+2; i++){

if(fact==n)

is=true;

fact=fact*i;

}

return is; }

Using this function, write another function void factarr(int a[], bool fact[], int size), in pseudocode, that determines the factorials in your array. When your function call is over, the array fact should be a parallel array to a where each spot holds true if the corresponding element of a is a fact, and false if it’s not.

4.Translate your pseudocode from 3 into C++ code. Add a main function that calls the function appropriately.

Answer 1

The explanation is done in the code itself. If you have any queries write a comment. If you have understood upvote. Thank you. I have written in the same as It has given

SOLUTION 1:

minimum(int a[]){
   min=a[0];
   //iterate through the array if there are any elements which are less than minimum update and return
   for(i=0;i<(size of array );i++){
       if(a[i]<min)
       min=a[i];
   }
   return min;
}

SOLUTION 2:

#include <bits/stdc++.h>
using namespace std;

int minimum( int a[],int size){
   int min=a[0];
   //iterate through the array if there are any elements which are less than minimum update and return
   for(int i=0;i<size;i++){
       if(a[i]<min)
       min=a[i];
   }
   //return minimum
   return min;
}
int main(){
   int a[]={10,20,30,5,9,70};
   cout<<"Minimum number is "<<minimum(a,(sizeof(a)/sizeof(*a)));
}

code Image:

OUTPUT:

SOLUTION 3:

//this function is calculating that the given number is factorial of some number or not like 120 is a factorial of 5 it give trrue if we 120 as input if we give 100 it will give it as false since it is not an factorial any number like it cannot obtained in the factorial way

bool isfact(int n){

bool is=false;

int fact=1;

for(int i=1; i<n+2; i++){

if(fact==n)

is=true;

fact=fact*i;

}

return is; }

factarray function :

//fact array for storing the array whether that it is a fact or
// not and store it in the fact array,
void factarr(int a[],bool fact[],int size]){
   for(int i=0;i<size;i++){
       fact[i]=isfact(a[i])
   }

}

SOLUTION 4:

#include <bits/stdc++.h>
using namespace std;

bool isfact(int n){
   bool is=false;
   int fact=1;
   for(int i=1; i<n+2; i++){
   if(fact==n)
       is=true;
   fact=fact*i;
   }
   return is;
}
//fact array for storing the array whether that it is a fact or
// not and store it in the fact array,
void factarr(int a[],bool fact[],int size){
   for(int i=0;i<size;i++){
       //call the fact function
       fact[i]=isfact(a[i]);
   }
   cout<<" If written 1 at the end means true if 0 false"<<"\n";
   for(int i=0;i<size;i++){
       cout<<a[i]<<" It is "<<fact[i]<<"\n";
   }
  
}

int main(){

//declare the array
   int a[]={120,100,720,1,2,80};

//i have written the fact bool array of size equal to the array since it needs to the passed to the //function
   bool fact[6];
   factarr(a,fact,6);
  
}

CODE IMAGE:

CODE OUTPUT: