C ++Write a function, anyThree (int a[], int n), that returns true if the value 3 appears in the array exactly 3 times, and no 3's are next to each other. The parameter n will be greater than or equal to 0.
Homework Answers
Function:
bool anyThree (int a[], int n) //function
{
int threes=0; //to count number of 3s in array.
for(int i=0; i<n; i++)
{
if(a[i]==3) //if number is 3 then incrementing the count of
3s
threes++;
if(a[i]==3 && a[i-1]==3 && i!=0) //if two 3s are
next to each other then return false.
return false;
}
if(threes==3) //if number of 3's in array are 3 then return
true.
return true;
return false; //if number of 3's in array are not equal to 3 then
return false.
}
![bool anyThree (int a[], int n) //function { int threes=0; //to count number of 33 in array. for(int i=0; i<n; i++) { if(a[i]=](http://img.homeworklib.com/questions/3bac2bf0-0abf-11eb-92e0-57dc117760f4.png?x-oss-process=image/resize,w_560)
Program:
#include<bits/stdc++.h>
using namespace std;
bool anyThree (int a[], int n) //function
{
int threes=0; //to count number of 3s in array.
for(int i=0; i<n; i++)
{
if(a[i]==3) //if number is 3 then incrementing the count of
3s
threes++;
if(a[i]==3 && a[i-1]==3 && i!=0) //if two 3s are
next to each other then return false.
return false;
}
if(threes==3) //if number of 3's in array are 3 then return
true.
return true;
return false; //if number of 3's in array are not equal to 3 then
return false.
}
int main()
{ //declaring and calling the function and printing the
result.
int a[] = {3, 1, 3, 1, 3};
cout << anyThree(a, 5) << endl;
int b[] = {3, 1, 3, 3};
cout << anyThree(b, 4) << endl;
int c[] = {3, 4, 3, 3, 4};
cout << anyThree(c, 5) << endl;
int d[] = {3};
cout << anyThree(d, 1) << endl;
return 0;
}
![1 2 3 #include<bits/stdc++.h> using namespace std; bool anyThree (int a[], int n) //function 4 int threes=0; //to count numbe](http://img.homeworklib.com/questions/3c4e5fb0-0abf-11eb-bbe9-f7a4d05483c6.png?x-oss-process=image/resize,w_560)
output:
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