A geostationary satellite is 42000 km above the earth surface. If the satellite latitude is 49o north with respect to the earth station and the spherical earth mean radius is 6371 km. Calculate the satellite angle EL and the polarization angle ψ
A geostationary satellite is 42000 km above the earth surface. If the satellite latitude is 49o...
A satellite is in orbit around Earth at a height of 120 km above Earth’s surface. Find the orbital speed of the satellite. (Mass of the earth is 6*1024 kg and the radius of Earth is 6371 km)
A satellite travels around Earth in uniform circular motion at an altitude of 35,850 km above Earth’s surface. The satellite is in geosynchronous orbit. In the below figure, the satellite moves counterclockwise (ABCDA). (State directions in terms of the x- and y-axes.) The radius of Earth is 6371 km. What is the direction of the satellite’s average velocity for one quarter of an orbit, starting at A and ending at B? Enter the answer in degrees where negative indicates an...
A geostationary communications satellite orbits the earth directly above the equator at an altitude of 34800 km .Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.Would this delay be noticeable in a conversation?
A geostationary satellite is a satellite located in an orbit such that it remains above the same point on the Earth’s surface. [Assume it takes 23 hours 56 minutes 4.09 seconds for the Earth to spin around once.] a) What is the angular velocity of such a satellite? b) What is the altitude of such a satellite? c) Calculate the period of a satellite orbiting 200km above the Earth.
A 345 kg satellite is orbiting 15500 km above the surface of Earth. The mass and radius of Earth are 5.972e+24 kg and 6378 km respectively. What is the kinetic energy of the satellite?
A geostationary orbit is one in which a satellite orbits the Earth (in a circular orbit) in the same time as it takes the Earth to make one full rotation with respect to the stars. a) Given the mass of the Earth, calculate the distance of a geostationary satellite from the center of the Earth. b) If you were standing on the equator with the geostationary satellite at your zenith, how long would it take to receive a radio signal?...
Calculate the period of a satellite orbiting the Moon, 96 km above the Moon's surface. Ignore effects of the Earth. The radius of the Moon is 1740 km..
If a satellite circulate around the earth at a height of 5,113.68 km above the earth's surface, given the earth radius is 3958.8 miles and mass is 5.98 x1024 kg, use G=6.67x 10-11 Nm2/kg2, find the period of this satellite in unit hours?
Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit has an orbital period of exactly one day. Assume a spherical Earth, and use the following constants (taken from Vallado, David A., Fundamentals of Astrodynamics and Applications, 2nd ed. 2001) Gravitational constant: G 6.673 x 10-20 km Radius of the Earth: Re = 6378.137 km 1024 kg Mass of the Earth: Me = 5.9733328 x Round your final answer to four...
1. A satellite 300 km above the surface of the Earth emits a radio wave pulse (wavelength = 25.0 m), Calculate the transit time for the wave to reach the surface of the Earth.