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A house has an indoor temperature of 336 K while the outdoor temperature is 280 K....

A house has an indoor temperature of 336 K while the outdoor temperature is 280 K. If there is a steady heat transfer rate of 1,855 W through a window of the house, what is the rate of entropy generation in this process in W/K?

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Answer #1

Entropy generation = Q(1/lower temp -1/higher temp)

1885*(1/280-1/336) = 1.122 W/ K

Actually principle behind this expression is lower temp gain heat so positive while high temperature lose heat so negative

There differenence is entropy generation

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