M=1470kg temp change =30C
Heat required to heat water =1470×4186×30=18.46×10^7J
Let energy supplied = Q=75/100Q+heat required to heat water
Q-75/100Q=18.46×10^7
0.925Q=18.46×10^7
Q=19.96×10^7J
1kwh=3.6×10^6
19.96×10^7=55.4kwh
Cost =55.4×9cents=499cents
VIt=55.4
220×I×4.05=55.4
I=0.062A
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