A ball is shot from the top of a building with an initial velocity of 19...
A ball is shot from the top of a building with an initial velocity of 19 m/s at an angle θ = 45 ∘ above the horizontal. Part A What are the x and y components of the initial velocity? Express your answers using two significant figures. Enter your answers numerically separated by a comma. Part B If a nearby building is the same height and 58 m away, how far below the top of the building will the ball strike the nearby building? Express your answer using two significant figures.
Homework Answers
vx = 19 cos 45 = 13 m/s
vy = 19 sin 45 = 13 m/s
========
mition along horizontal
d = vx * t
t = 58 / 13.435 = 4.317 s
motion along vertical
- h = vy * t - 0.5 g t^2
-h = - 33.32 m
h = 33 m
=======
Comment in case any doubt, will reply for sure.. Goodluck
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