Replacing I by Torque
C1 by Moment of Inertia J1
C2 by Moment of Inertia J2
C3 by Moment of Inertia J3
L1 by K1
L2 by K2
L3 by K3
L4 by K4
R1 by B1
R2 by B2
We get rotational torque analogy
3. In Figure 2, what is the direction of the current induced in the res the switch is closed? the instant ε' s Figure 2
Evaluate the following residues. A. (10 points) Res ( rez B. (10 points) Res (2.44 +3:1)
Compute the radii of gyration about both centroidal axes for the following structural steel shape L4 x 3 x 1/2 Z r X y.y k Weight per ft Area Thickness I z z Tan Ур х, in.3 in. in.4 in 3 in. iп. lb in: in in. in. in. in. in. in in in 0.827 15/1h 11.1 3.25 5.05 1.25 1.33 3.41 0.750 2.42 1.12 0.864 2.03 0.406 0.639 0.543 L4 x 3 x 1/2 Z r X y.y k...
+3 7 اذا كانت الدالة - 22( z2 + 2) = (2)f فان (0,Res ( f هو ه م 2 م لا | -
Problem #One 3 kw/m 3 KN A BA 2 m 6 m 3 m res wtant internal loadings achng Determine the on the cross section through point D
Res) flant Gain / 425t 2 Ca) wlen PID-Contrel Gainsks) Klsts)(it Spetel the Yoot - locus (Plot the keoKeoe) : abnt oPen-loop Plart's respause YS)-GCS)us) /(mit step Tu) x ax3:time t) Plot the g raph (usng muene (aplace fam) Y RTS pesfonse YIE) ConPare on a bant Closes-loop system's resparse ys= T19)r)/(gan k = 14) Plot the Yaxis: pespaye E aPh Cushy inere larhce torm) L4:CGiven Gis)SH Plot the root 10cus on whan p-lantnGain is es)=k Pectively aud Po-Cantrol Gain...
L4' : Find 11,12 and Vi in the following circuit. 4Ω 2Ω 3 A 6Ω 4 6Ω 40 1, 6Ω 2Ω 4Ω An ammeter model consists of an ideal ammeter in series with a 202 resisto m resistor R as shown below. The al 5
Compute the left and right Riemann sums - L4 and R4, respictively - for F(x) =(4-x2)1/2 on [-2, 2] and compare their values.
11.Draw the DC equivalent circuit: R1 L4 し1 C1 1GF し2 2.57uH 37.6mH 1TH C3 1uF R3 5kQ R2 11.Draw the DC equivalent circuit: R1 L4 し1 C1 1GF し2 2.57uH 37.6mH 1TH C3 1uF R3 5kQ R2
Problem 2: (CCVS) Find I2, l4 and Vac 3.5 po 11=12 + 3A 10V 12 (SVA) Il 9A I411A