A study found that the mean amount of time cars spent in drive-throughs of a certain...
A study found that the mean amount of time cars spent in drive-throughs of a certain fast-food restaurant was
139.9
seconds. Assuming drive-through times are normally distributed with a standard deviation of
31
seconds, complete parts (a) through (d) below.
Click here to view the standard normal distribution table (page 1).
LOADING...
Click here to view the standard normal distribution table (page 2).
LOADING...
(a) What is the probability that a randomly selected car will get through the restaurant's drive-through in less than
88
seconds?
The probability that a randomly selected car will get through the restaurant's drive-through in less than
88
seconds is
nothing
.
(Round to four decimal places as needed.)
Homework Answers
a) P(Mean less than 88)
= P(X < 88)
= P(z < (88 - 139.9)/31)
= P(z < -1.67)
= 0.0470
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