Balance the following nuclear reaction:
22890Th --> _____ + 22888Ra
a. 42He
b. 2 0+1e (positron)
c. 2 0+1e (beta particle)
d. 2 00gamma
Ans is C
22890Th --> __2+___ + 22888Ra
In the above equation same atomic masses and different atomic numbers. it liberates 2 beta particles are liberated
Balance the following nuclear reaction: 22890Th --> _____ + 22888Ra a. 42He b. 2 0+1e (positron)...
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