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An unknown metal has a mass of 74.1 g. When 1.90 x 103 J of heat are added to the sample, the sample temperature changes by 3

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Answer #1

Q = mass * specific heat * ∆T

1.90 * 10^3 = 74.1 * C * 34.1

C = 0.752 J/g°C

This is potassium ....( 0.750 J/g°C

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