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- Part A- A small plane that moves along a 1.5 km long runway during take-off celerates from rest to a speed of 10.8 m/s in 4
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Answer #1

Mass of the plane = m = 830 kg

Initial speed of the plane = V1 = 0 m/s

Final speed of the plane = V2 = 10.8 m/s

Length of the runway = L = 1.5 km = 1500 m

Time period of acceleration = T = 4.53 min = 4.53 x (60) sec = 271.8 sec

Total work done on the plane = W

The change in kinetic energy of the plane is equal to the total work done on the plane.

W = 4.8 x 104 J

Total work done on the plane = 4.8 x 104 J

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