Question

dolocatorsassignment-takeätak In the above redox reaction use aidation masbers to identify the element oxidiuzed, the elesent seduced, the oodining agent and the sedocing agent name of the clement oxidized name of the clement rodacedt formula of the coudizing agent formala of the seducing agent Retry Enlire Group more group attempts remaining

Answer 1

The reaction is 2MnO₄^- + 5Co⁺ + 16H⁺   2Mn⁺² + 5Co⁺² + 8H₂O

The oxidation state of Cobalt is +1 in the left side and +2 in the right side. The oxidation number of cobalt increases during the reaction which suggests that Cobalt has undergone oxidation in the process.

Let us calculate the oxidation number of Mn in MnO₄^-.

Let us assume the oxidation number of Mn in MnO₄^- as x.

We know the oxidation number of oxygen is -2

Then, x. (-2. 4) = -1

OR, x = +7

Hence the oxidation number of Mn in MnO₄^- is +7.

That means during the reaction the oxidation number of Mn decreases from +7 to +2.

Which suggests that Mn is reduced during the process.

From the definition we know, that the compound which undergoes reduction is called oxidising agent and the compound which undergoes oxidation is a reducing agent.

Final answer:

Name of the element oxidised: Co+

Name of the element reduced: MnO₄^-

Formula of the oxidising agent: MnO₄^-

Formula of the reducing agent: Co+