as we know that 1 atm = 760 torr
H is enthalpy of vaporisation
R = 8.314472 J mol−1 K−1
given T1 = 97.2 + 273 K = 370.2 K
T2 = 82.3+273K = 355.3 K
P2 = 617 torr
P1 = 760 torr
therefore
using clausius clapeyron equation
ln[ P2 / P1 ] = [ H / R ][ (1 / T1) - (1 / T2) ]
ln [617/760] = [H/8.314472][(1/370.2) - (1/355.3)]
therefore H = 17290 J/mol
wbact is the AHeuap) of c liqu Pressure of le torr at 82.3ee and a boiling...
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