Question

One model of the length LACLLACL of a person's anterior cruciate ligament, or ACL, relates it to the person's height hh with the linear function

LACL=0.04606h−(41.29 mm)LACL=0.04606h−(41.29 mm)

This relationship does not change significantly with age, gender, or weight. If a basketball player has a height of 2.13 m,2.13 m, approximately how long is his ACL?

LACL=LACL=

mmmm

If a stress of 1.05×107 N/m21.05×107 N/m2 is applied to his ligament, how much will it stretch? The Young's modulus for the ACL is 1.10×108 N/m2.1.10×108 N/m2.

change in LACLLACL:

mm

Answer 1