In a box there are 6 red and 4 blue balls. By chance, one balli s taken out. If the balli s red, it is put aside. If the balli s blue, it is returned into the box. What is the probability that the second ball taken will be blue?
Tree diagram
P(second ball taken will be blue) = P(first ball was red and second ball is blue) + P(first ball is blue and second ball is blue)
= (6/10 x 4/9) + (4/10 x 4/10)
= 0.4267
In a box there are 6 red and 4 blue balls. By chance, one balli s...
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Please ignore the section discussing the 3 diagrams.
Tree Diagrams and Probability A box contains 4 red and 8 blue balls. Three balls are drawn from the box. Print the 3 different tree diagrams. 1. Complete the symbolic tree diagram by placing appropriate symbols on the branches and at the ends of the branches as indicated 2. Assuming the balls are drawn without replacement, complete the WO R diagram by placing appropriate probabilities on the branches and at the ends...
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