box 1 3 blue and 2 ref balls. box 2 has 1 blue and 4 red...

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box 1 3 blue and 2 ref balls. box 2 has 1 blue and 4 red...

box 1 3 blue and 2 ref balls. box 2 has 1 blue and 4 red balls. a box is selected randomly and a ball is drawn. what is the probability that now box2 has no blue ball

math Statistics-And-Probability

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Answer 1

Answer #1

Box2 has no blue ball implies that we selected box2 and we got blue ball from it.

P(box 2 has no blue ball) = P(box 2 selected) * P(blue ball in box 2 selected)

Hence, 1/10 or 0.1 is the probability that now box 2 has no blue ball.

Please comment if any doubt. Thank you.

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Answer 2

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