Question

Has to be written in C++

Write a program that asks the user to enter the month (1-12) and the year (0-2019). Validate the input and print an error and stop the program if an invalid month or year was entered. The program should then display the number of days in that month. Use the following criteria to identify leap years:

1. Determine whether the year is divisible by 100. If it is, then it is a leap year if and only if it is divisible by 400. For example, 2000 is a leap year but 2100 is not.

2. If the year is not divisible by 100, then it is a leap year if and only if it is divisible by 4. For example, 2008 is a leap year but 2009 is not.

Answer 1

C++ program :-

#include <iostream>
using namespace std;

int main()
{
   int days=0;
int month;
int year;
int valid = 0;
  
while(valid == 0){
cout<< "Please enter the year : "<<endl;
cin>>year;
  
if(year > 0 && year < 2019)
valid = 1;
else
cout<<"Please enter valid year (0-2019)"<<endl;
}
  
valid = 0;
  
  
while(valid == 0){
cout<< "Please enter the month : "<<endl;
cin>>month;
  
if(month >= 1 && month <= 12)
valid = 1;
else
cout<<"Please enter valid month [1-12]"<<endl;
}
  
  
   if( month == 2)
   {
       if((year%400==0) || (year%4==0 && year%100!=0))  
           days = 29;
       else  
           days = 28;
   }
   //months which has 31 days
   else if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8
   ||month == 10 || month==12)  
       days = 31;
   else       
       days = 30;

   cout<<endl<<"Number of Days in month ="<<month<<", year = "<<year<<" : "<<days;

   return 0;
}

Output :-