A certain reaction is first order, and 570 ss after initiation of the reaction, 35.6 %% of the reactant remains.
Part A: What is the rate constant for this reaction? Express your answer with the appropriate units.
Part B: At what time after initiation of the reaction will 10 %% of the reactant remain? Express your answer with the appropriate units.
A certain reaction is first order, and 570 ss after initiation of the reaction, 35.6 %%...
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t k Part A The reactant concentration in a zero-order reaction was 8.00×10−2 MM after 130 ss and 4.00×10−2 MM after 380 ss . What is...
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k−k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k−k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t kk A.) The reactant concentration in a zero-order reaction was 0.100 MM after 165 ss and 4.00×10−2 MM after 305 ss . What is the...
A certain first-order reaction ( A products) has a rate constant of 5.10x10-35-1 at 45 °C. How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration? Express your answer with the appropriate units. View Available Hint(s) ? HA Value O Units Submit Part B A certain second-order reaction (B>products) has a rate constant of 1.10x10-3M-1.s-1 at 27°C and an initial half-life of 212 s . What is the concentration...
+ Half-life for First and Second Order Reactions 11 of 11 The half-life of a reaction, t1/2, is the time it takes for the reactant concentration A to decrease by half. For example, after one half-Me the concentration falls from the initial concentration (Alo to A\o/2, after a second half-life to Alo/4 after a third half-life to A./8, and so on. on Review Constants Periodic Table 11/25 For a second-order reaction, the half-life depends on the rate constant and the...
Part A The reactant concentration in a zero-order reaction was 6.00×10?2M after 105 s and 4.00×10?2M after 335 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary,...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...
Part A The reactant concentration in a zero-order reaction was 7.00×10−2M after 105 s and 1.50×10−2Mafter 345 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...
Part A The rate constant for a certain reaction is k = 6.30×10−3 s−1 . If the initial reactant concentration was 0.150 M, what will the concentration be after 9.00 minutes? Express your answer with the appropriate units. Part B A zero-order reaction has a constant rate of 4.90×10−4 M/s. If after 60.0 seconds the concentration has dropped to 2.50×10−2 M, what was the initial concentration? Express your answer with the appropriate units.