1b. You wish to make a 0.395 M perchloric acid solution from a stock solution of...
1b. You wish to make a 0.395 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid must you add to obtain a total volume of 75.0 mL of the dilute solution?
1c. In the laboratory you dilute 4.36 mL of a concentrated 12.0 M perchloric acid solution to a total volume of 50.0 mL. What is the concentration of the dilute solution?
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1b. You wish to make a 0.395 M perchloric acid solution from a
stock solution of...
You wish to make a 0.249 M hydrobromic acid solution from a stock solution of 12.0...
You wish to make a 0.249 M hydrobromic acid solution from a stock solution of 12.0 M hydrobromic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? __mL You wish to make a 0.112 M nitric acid solution from a stock solution of 12.0 M nitric acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution? __mL In the...
You wish to make a 0.257 M nitric acid solution from a stock solution of 3.00...
You wish to make a 0.257 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? Submit Answer Retry Entire Group 9 more group attempts remaining
You wish to make a 0.445 M hydrochloric acid solution from a stock solution of 12.0...
You wish to make a 0.445 M hydrochloric acid solution from a stock solution of 12.0 M hydrochloric acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution?
You wish to make a 0.252 M nitric acid solution from a stock solution of 12.0...
You wish to make a 0.252 M nitric acid solution from a stock solution of 12.0 M nitric acid. How much-concentrated acid must you add to obtain a total volume of 175 mL of the dilute solution?
You wish to make a 0.135 M nitric acid solution from a stock solution of 3.00...
You wish to make a 0.135 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution? ml
Question 1: In the laboratory you dilute 3.33 mL of a concentrated 6.00 M hydrochloric acid...
Question 1: In the laboratory you dilute 3.33 mL of a concentrated 6.00 M hydrochloric acid solution to a total volume of 75.0 mL. What is the concentration of the dilute solution? M Question 2: You wish to make a 0.153 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution? mL Thank-you!
Gonca the References to importatif eded for the You wish to make a 0.266 M perchloric...
Gonca the References to importatif eded for the You wish to make a 0.266 M perchloric acid solution from a stock solution of 6.00 M perchloric acid How much concentrated dilute solution you to obtain a lotal volume of 50.0 ml of the Try Another Version
I do not need to see work shown, just the correct exact answers. Please be clear...
I do not need to see work shown, just the correct exact answers.
Please be clear on what the answers are. I will give thumbs up if
correct.
4-10
You wish to make a 0.136 M perchloric acid solution from a stock solution of 6.00 M perchloric acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution? mt In the laboratory you dilute 4.47 mL of a concentrated 3.00 M...
You wish to make a 0.132 M nitric acid solution from a stock solution of 6.00...
You wish to make a 0.132 M nitric acid solution from a stock solution of 6.00 M nitric acid. How much concentrated acid must you add to obtain total volume of 175 mL of the dilute solution? Submit Answer Retry Entire Group more group attempts remaining 1 pts are In the laboratory a student combines 37.6 ml of a 0.289 M potassium sulfide solution with 22.5 ml of a 0.629 M potassium carbonate solution What is the final concentration of...
1- How many milliliters of an aqueous solution of 0.122 M aluminum chloride is needed to...
1- How many milliliters of an aqueous solution of 0.122 M aluminum chloride is needed to obtain 13.9 grams of the salt? 2- In the laboratory you dissolve 15.7 g of barium sulfide in a volumetric flask and add water to a total volume of 250 . mL. What is the molarity of the solution? 3- In the laboratory you dilute 4.43 mL of a concentrated 6.00 M hydroiodic acid solution to a total volume of 50.0 mL. What is...
You wish to make a 0.257 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? Submit Answer Retry Entire Group 9 more group attempts remaining
You wish to make a 0.135 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution? ml
Gonca the References to importatif eded for the You wish to make a 0.266 M perchloric acid solution from a stock solution of 6.00 M perchloric acid How much concentrated dilute solution you to obtain a lotal volume of 50.0 ml of the Try Another Version
I do not need to see work shown, just the correct exact answers.
Please be clear on what the answers are. I will give thumbs up if
correct.
4-10
You wish to make a 0.136 M perchloric acid solution from a stock solution of 6.00 M perchloric acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution? mt In the laboratory you dilute 4.47 mL of a concentrated 3.00 M...
You wish to make a 0.132 M nitric acid solution from a stock solution of 6.00 M nitric acid. How much concentrated acid must you add to obtain total volume of 175 mL of the dilute solution? Submit Answer Retry Entire Group more group attempts remaining 1 pts are In the laboratory a student combines 37.6 ml of a 0.289 M potassium sulfide solution with 22.5 ml of a 0.629 M potassium carbonate solution What is the final concentration of...
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