895 J of heat was required to increase the temperature of 29.6 g of aluminum initially at 22.5°C.
What is the final temperature of the aluminum? Specific heat capacity of aluminum is 0.903 J/g°C.
Given:
Q = 895 J
m = 29.6 g
C = 0.903 J/g.oC
Ti = 22.5 oC
use:
Q = m*C*(Tf-Ti)
895.0 = 29.6*0.903*(Tf-22.5)
Tf -22.5 = 33.5 oC
Tf = 56.0 oC
Answer: 56.0 oC
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